Optimal. Leaf size=133 \[ -\frac {12 i d^2 (c+d x) \text {Li}_2\left (e^{i (e+f x)}\right )}{a f^3}+\frac {6 d (c+d x)^2 \log \left (1-e^{i (e+f x)}\right )}{a f^2}-\frac {(c+d x)^3 \cot \left (\frac {e}{2}+\frac {f x}{2}\right )}{a f}-\frac {i (c+d x)^3}{a f}+\frac {12 d^3 \text {Li}_3\left (e^{i (e+f x)}\right )}{a f^4} \]
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Rubi [A] time = 0.28, antiderivative size = 133, normalized size of antiderivative = 1.00, number of steps used = 7, number of rules used = 7, integrand size = 21, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.333, Rules used = {3318, 4184, 3717, 2190, 2531, 2282, 6589} \[ -\frac {12 i d^2 (c+d x) \text {Li}_2\left (e^{i (e+f x)}\right )}{a f^3}+\frac {6 d (c+d x)^2 \log \left (1-e^{i (e+f x)}\right )}{a f^2}-\frac {(c+d x)^3 \cot \left (\frac {e}{2}+\frac {f x}{2}\right )}{a f}-\frac {i (c+d x)^3}{a f}+\frac {12 d^3 \text {Li}_3\left (e^{i (e+f x)}\right )}{a f^4} \]
Antiderivative was successfully verified.
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Rule 2190
Rule 2282
Rule 2531
Rule 3318
Rule 3717
Rule 4184
Rule 6589
Rubi steps
\begin {align*} \int \frac {(c+d x)^3}{a-a \cos (e+f x)} \, dx &=\frac {\int (c+d x)^3 \csc ^2\left (\frac {e}{2}+\frac {f x}{2}\right ) \, dx}{2 a}\\ &=-\frac {(c+d x)^3 \cot \left (\frac {e}{2}+\frac {f x}{2}\right )}{a f}+\frac {(3 d) \int (c+d x)^2 \cot \left (\frac {e}{2}+\frac {f x}{2}\right ) \, dx}{a f}\\ &=-\frac {i (c+d x)^3}{a f}-\frac {(c+d x)^3 \cot \left (\frac {e}{2}+\frac {f x}{2}\right )}{a f}-\frac {(6 i d) \int \frac {e^{2 i \left (\frac {e}{2}+\frac {f x}{2}\right )} (c+d x)^2}{1-e^{2 i \left (\frac {e}{2}+\frac {f x}{2}\right )}} \, dx}{a f}\\ &=-\frac {i (c+d x)^3}{a f}-\frac {(c+d x)^3 \cot \left (\frac {e}{2}+\frac {f x}{2}\right )}{a f}+\frac {6 d (c+d x)^2 \log \left (1-e^{i (e+f x)}\right )}{a f^2}-\frac {\left (12 d^2\right ) \int (c+d x) \log \left (1-e^{2 i \left (\frac {e}{2}+\frac {f x}{2}\right )}\right ) \, dx}{a f^2}\\ &=-\frac {i (c+d x)^3}{a f}-\frac {(c+d x)^3 \cot \left (\frac {e}{2}+\frac {f x}{2}\right )}{a f}+\frac {6 d (c+d x)^2 \log \left (1-e^{i (e+f x)}\right )}{a f^2}-\frac {12 i d^2 (c+d x) \text {Li}_2\left (e^{i (e+f x)}\right )}{a f^3}+\frac {\left (12 i d^3\right ) \int \text {Li}_2\left (e^{2 i \left (\frac {e}{2}+\frac {f x}{2}\right )}\right ) \, dx}{a f^3}\\ &=-\frac {i (c+d x)^3}{a f}-\frac {(c+d x)^3 \cot \left (\frac {e}{2}+\frac {f x}{2}\right )}{a f}+\frac {6 d (c+d x)^2 \log \left (1-e^{i (e+f x)}\right )}{a f^2}-\frac {12 i d^2 (c+d x) \text {Li}_2\left (e^{i (e+f x)}\right )}{a f^3}+\frac {\left (12 d^3\right ) \operatorname {Subst}\left (\int \frac {\text {Li}_2(x)}{x} \, dx,x,e^{2 i \left (\frac {e}{2}+\frac {f x}{2}\right )}\right )}{a f^4}\\ &=-\frac {i (c+d x)^3}{a f}-\frac {(c+d x)^3 \cot \left (\frac {e}{2}+\frac {f x}{2}\right )}{a f}+\frac {6 d (c+d x)^2 \log \left (1-e^{i (e+f x)}\right )}{a f^2}-\frac {12 i d^2 (c+d x) \text {Li}_2\left (e^{i (e+f x)}\right )}{a f^3}+\frac {12 d^3 \text {Li}_3\left (e^{i (e+f x)}\right )}{a f^4}\\ \end {align*}
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Mathematica [A] time = 1.25, size = 164, normalized size = 1.23 \[ \frac {2 \sin \left (\frac {1}{2} (e+f x)\right ) \left (f^3 \csc \left (\frac {e}{2}\right ) (c+d x)^3 \sin \left (\frac {f x}{2}\right )+2 \sin \left (\frac {1}{2} (e+f x)\right ) \left (6 i d^2 f (c+d x) \text {Li}_2\left (e^{-i (e+f x)}\right )-\frac {i f^3 (c+d x)^3}{-1+e^{i e}}+3 d f^2 (c+d x)^2 \log \left (1-e^{-i (e+f x)}\right )+6 d^3 \text {Li}_3\left (e^{-i (e+f x)}\right )\right )\right )}{f^4 (a-a \cos (e+f x))} \]
Antiderivative was successfully verified.
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fricas [C] time = 0.83, size = 467, normalized size = 3.51 \[ -\frac {d^{3} f^{3} x^{3} + 3 \, c d^{2} f^{3} x^{2} + 3 \, c^{2} d f^{3} x + c^{3} f^{3} - 6 \, d^{3} {\rm polylog}\left (3, \cos \left (f x + e\right ) + i \, \sin \left (f x + e\right )\right ) \sin \left (f x + e\right ) - 6 \, d^{3} {\rm polylog}\left (3, \cos \left (f x + e\right ) - i \, \sin \left (f x + e\right )\right ) \sin \left (f x + e\right ) - {\left (-6 i \, d^{3} f x - 6 i \, c d^{2} f\right )} {\rm Li}_2\left (\cos \left (f x + e\right ) + i \, \sin \left (f x + e\right )\right ) \sin \left (f x + e\right ) - {\left (6 i \, d^{3} f x + 6 i \, c d^{2} f\right )} {\rm Li}_2\left (\cos \left (f x + e\right ) - i \, \sin \left (f x + e\right )\right ) \sin \left (f x + e\right ) - 3 \, {\left (d^{3} e^{2} - 2 \, c d^{2} e f + c^{2} d f^{2}\right )} \log \left (-\frac {1}{2} \, \cos \left (f x + e\right ) + \frac {1}{2} i \, \sin \left (f x + e\right ) + \frac {1}{2}\right ) \sin \left (f x + e\right ) - 3 \, {\left (d^{3} e^{2} - 2 \, c d^{2} e f + c^{2} d f^{2}\right )} \log \left (-\frac {1}{2} \, \cos \left (f x + e\right ) - \frac {1}{2} i \, \sin \left (f x + e\right ) + \frac {1}{2}\right ) \sin \left (f x + e\right ) - 3 \, {\left (d^{3} f^{2} x^{2} + 2 \, c d^{2} f^{2} x - d^{3} e^{2} + 2 \, c d^{2} e f\right )} \log \left (-\cos \left (f x + e\right ) + i \, \sin \left (f x + e\right ) + 1\right ) \sin \left (f x + e\right ) - 3 \, {\left (d^{3} f^{2} x^{2} + 2 \, c d^{2} f^{2} x - d^{3} e^{2} + 2 \, c d^{2} e f\right )} \log \left (-\cos \left (f x + e\right ) - i \, \sin \left (f x + e\right ) + 1\right ) \sin \left (f x + e\right ) + {\left (d^{3} f^{3} x^{3} + 3 \, c d^{2} f^{3} x^{2} + 3 \, c^{2} d f^{3} x + c^{3} f^{3}\right )} \cos \left (f x + e\right )}{a f^{4} \sin \left (f x + e\right )} \]
Verification of antiderivative is not currently implemented for this CAS.
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giac [F] time = 0.00, size = 0, normalized size = 0.00 \[ \int -\frac {{\left (d x + c\right )}^{3}}{a \cos \left (f x + e\right ) - a}\,{d x} \]
Verification of antiderivative is not currently implemented for this CAS.
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maple [B] time = 0.16, size = 468, normalized size = 3.52 \[ -\frac {6 i d^{2} c \,e^{2}}{a \,f^{3}}-\frac {6 d \,c^{2} \ln \left ({\mathrm e}^{i \left (f x +e \right )}\right )}{a \,f^{2}}+\frac {6 d \,c^{2} \ln \left ({\mathrm e}^{i \left (f x +e \right )}-1\right )}{a \,f^{2}}-\frac {6 d^{3} e^{2} \ln \left ({\mathrm e}^{i \left (f x +e \right )}\right )}{a \,f^{4}}+\frac {6 d^{3} e^{2} \ln \left ({\mathrm e}^{i \left (f x +e \right )}-1\right )}{a \,f^{4}}-\frac {12 i d^{2} c e x}{a \,f^{2}}-\frac {2 i \left (d^{3} x^{3}+3 c \,d^{2} x^{2}+3 c^{2} d x +c^{3}\right )}{f a \left ({\mathrm e}^{i \left (f x +e \right )}-1\right )}+\frac {6 i d^{3} e^{2} x}{a \,f^{3}}-\frac {6 i d^{2} c \,x^{2}}{a f}+\frac {6 d^{3} \ln \left (1-{\mathrm e}^{i \left (f x +e \right )}\right ) x^{2}}{a \,f^{2}}-\frac {6 d^{3} \ln \left (1-{\mathrm e}^{i \left (f x +e \right )}\right ) e^{2}}{a \,f^{4}}-\frac {12 i d^{2} c \polylog \left (2, {\mathrm e}^{i \left (f x +e \right )}\right )}{a \,f^{3}}+\frac {12 d^{3} \polylog \left (3, {\mathrm e}^{i \left (f x +e \right )}\right )}{a \,f^{4}}+\frac {12 d^{2} c e \ln \left ({\mathrm e}^{i \left (f x +e \right )}\right )}{a \,f^{3}}-\frac {12 d^{2} c e \ln \left ({\mathrm e}^{i \left (f x +e \right )}-1\right )}{a \,f^{3}}+\frac {12 d^{2} c \ln \left (1-{\mathrm e}^{i \left (f x +e \right )}\right ) x}{a \,f^{2}}+\frac {12 d^{2} c \ln \left (1-{\mathrm e}^{i \left (f x +e \right )}\right ) e}{a \,f^{3}}-\frac {12 i d^{3} \polylog \left (2, {\mathrm e}^{i \left (f x +e \right )}\right ) x}{a \,f^{3}}-\frac {2 i d^{3} x^{3}}{a f}+\frac {4 i d^{3} e^{3}}{a \,f^{4}} \]
Verification of antiderivative is not currently implemented for this CAS.
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maxima [B] time = 1.34, size = 959, normalized size = 7.21 \[ \text {result too large to display} \]
Verification of antiderivative is not currently implemented for this CAS.
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mupad [F] time = 0.00, size = -1, normalized size = -0.01 \[ \int \frac {{\left (c+d\,x\right )}^3}{a-a\,\cos \left (e+f\,x\right )} \,d x \]
Verification of antiderivative is not currently implemented for this CAS.
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sympy [F] time = 0.00, size = 0, normalized size = 0.00 \[ - \frac {\int \frac {c^{3}}{\cos {\left (e + f x \right )} - 1}\, dx + \int \frac {d^{3} x^{3}}{\cos {\left (e + f x \right )} - 1}\, dx + \int \frac {3 c d^{2} x^{2}}{\cos {\left (e + f x \right )} - 1}\, dx + \int \frac {3 c^{2} d x}{\cos {\left (e + f x \right )} - 1}\, dx}{a} \]
Verification of antiderivative is not currently implemented for this CAS.
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